8(x-3)-(6-2x)=3(x+2)-4(3-2x)

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Solution for 8(x-3)-(6-2x)=3(x+2)-4(3-2x) equation: 



8(x-3)-(6-2x)=3(x+2)-4(3-2x)

We move all terms to the left:

8(x-3)-(6-2x)-(3(x+2)-4(3-2x))=0

We add all the numbers together, and all the variables

8(x-3)-(-2x+6)-(3(x+2)-4(-2x+3))=0

We multiply parentheses

8x-(-2x+6)-(3(x+2)-4(-2x+3))-24=0

We get rid of parentheses

8x+2x-(3(x+2)-4(-2x+3))-6-24=0



We calculate terms in parentheses: -(3(x+2)-4(-2x+3)), so:

3(x+2)-4(-2x+3)

We multiply parentheses

3x+8x+6-12

We add all the numbers together, and all the variables

11x-6

Back to the equation:

-(11x-6)



We add all the numbers together, and all the variables

10x-(11x-6)-30=0

We get rid of parentheses

10x-11x+6-30=0

We add all the numbers together, and all the variables

-1x-24=0

We move all terms containing x to the left, all other terms to the right

-x=24

x=24/-1

x=-24

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