7(y-1)=3(y+1/3)

Solution for 7(y-1)=3(y+1/3) equation:

7(y-1)=3(y+1/3)

We move all terms to the left:

7(y-1)-(3(y+1/3))=0

We add all the numbers together, and all the variables

7(y-1)-(3(+y+1/3))=0

We multiply parentheses

7y-(3(+y+1/3))-7=0

We multiply all the terms by the denominator


7y*3))-(3(+y+1-7*3))=0

We add all the numbers together, and all the variables

7y*3))-(3(y-20))=0

We add all the numbers together, and all the variables

7y*3))-(3(y=0

Wy multiply elements

21y^2=0

a = 21; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·21·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{0}{42}=0$