3(a+5)=7a-1

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Solution for 3(a+5)=7a-1 equation: 



3(a+5)=7a-1

We move all terms to the left:

3(a+5)-(7a-1)=0

We multiply parentheses

3a-(7a-1)+15=0

We get rid of parentheses

3a-7a+1+15=0

We add all the numbers together, and all the variables

-4a+16=0

We move all terms containing a to the left, all other terms to the right

-4a=-16

a=-16/-4

a=+4

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