7(y-1)-6=-3(-9y+2)-6y

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Solution for 7(y-1)-6=-3(-9y+2)-6y equation: 



7(y-1)-6=-3(-9y+2)-6y

We move all terms to the left:

7(y-1)-6-(-3(-9y+2)-6y)=0

We multiply parentheses

7y-(-3(-9y+2)-6y)-7-6=0



We calculate terms in parentheses: -(-3(-9y+2)-6y), so:

-3(-9y+2)-6y

We add all the numbers together, and all the variables

-6y-3(-9y+2)

We multiply parentheses

-6y+27y-6

We add all the numbers together, and all the variables

21y-6

Back to the equation:

-(21y-6)



We add all the numbers together, and all the variables

7y-(21y-6)-13=0

We get rid of parentheses

7y-21y+6-13=0

We add all the numbers together, and all the variables

-14y-7=0

We move all terms containing y to the left, all other terms to the right

-14y=7

y=7/-14

y=-1/2

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