7(y-1)-6=-3(9y+2)-6y

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Solution for 7(y-1)-6=-3(9y+2)-6y equation: 



7(y-1)-6=-3(9y+2)-6y

We move all terms to the left:

7(y-1)-6-(-3(9y+2)-6y)=0

We multiply parentheses

7y-(-3(9y+2)-6y)-7-6=0



We calculate terms in parentheses: -(-3(9y+2)-6y), so:

-3(9y+2)-6y

We add all the numbers together, and all the variables

-6y-3(9y+2)

We multiply parentheses

-6y-27y-6

We add all the numbers together, and all the variables

-33y-6

Back to the equation:

-(-33y-6)



We add all the numbers together, and all the variables

7y-(-33y-6)-13=0

We get rid of parentheses

7y+33y+6-13=0

We add all the numbers together, and all the variables

40y-7=0

We move all terms containing y to the left, all other terms to the right

40y=7

y=7/40

y=7/40

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