7(y-1)-12=3(y+3)

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Solution for 7(y-1)-12=3(y+3) equation: 



7(y-1)-12=3(y+3)

We move all terms to the left:

7(y-1)-12-(3(y+3))=0

We multiply parentheses

7y-(3(y+3))-7-12=0



We calculate terms in parentheses: -(3(y+3)), so:

3(y+3)

We multiply parentheses

3y+9

Back to the equation:

-(3y+9)



We add all the numbers together, and all the variables

7y-(3y+9)-19=0

We get rid of parentheses

7y-3y-9-19=0

We add all the numbers together, and all the variables

4y-28=0

We move all terms containing y to the left, all other terms to the right

4y=28

y=28/4

y=7

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