3(2y+1)=4(y-5)

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Solution for 3(2y+1)=4(y-5) equation: 



3(2y+1)=4(y-5)

We move all terms to the left:

3(2y+1)-(4(y-5))=0

We multiply parentheses

6y-(4(y-5))+3=0



We calculate terms in parentheses: -(4(y-5)), so:

4(y-5)

We multiply parentheses

4y-20

Back to the equation:

-(4y-20)



We get rid of parentheses

6y-4y+20+3=0

We add all the numbers together, and all the variables

2y+23=0

We move all terms containing y to the left, all other terms to the right

2y=-23

y=-23/2

y=-11+1/2

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