7(y+8)+y=4(y+4)-5

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Solution for 7(y+8)+y=4(y+4)-5 equation: 



7(y+8)+y=4(y+4)-5

We move all terms to the left:

7(y+8)+y-(4(y+4)-5)=0

We add all the numbers together, and all the variables

y+7(y+8)-(4(y+4)-5)=0

We multiply parentheses

y+7y-(4(y+4)-5)+56=0



We calculate terms in parentheses: -(4(y+4)-5), so:

4(y+4)-5

We multiply parentheses

4y+16-5

We add all the numbers together, and all the variables

4y+11

Back to the equation:

-(4y+11)



We add all the numbers together, and all the variables

8y-(4y+11)+56=0

We get rid of parentheses

8y-4y-11+56=0

We add all the numbers together, and all the variables

4y+45=0

We move all terms containing y to the left, all other terms to the right

4y=-45

y=-45/4

y=-11+1/4

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