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6(x+2)=2(3x+4)+4
We move all terms to the left:
6(x+2)-(2(3x+4)+4)=0
We multiply parentheses
6x-(2(3x+4)+4)+12=0
We calculate terms in parentheses: -(2(3x+4)+4), so:We get rid of parentheses
2(3x+4)+4
We multiply parentheses
6x+8+4
We add all the numbers together, and all the variables
6x+12
Back to the equation:
-(6x+12)
6x-6x-12+12=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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