7(y+1)=2(2y+3)

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Solution for 7(y+1)=2(2y+3) equation: 



7(y+1)=2(2y+3)

We move all terms to the left:

7(y+1)-(2(2y+3))=0

We multiply parentheses

7y-(2(2y+3))+7=0



We calculate terms in parentheses: -(2(2y+3)), so:

2(2y+3)

We multiply parentheses

4y+6

Back to the equation:

-(4y+6)



We get rid of parentheses

7y-4y-6+7=0

We add all the numbers together, and all the variables

3y+1=0

We move all terms containing y to the left, all other terms to the right

3y=-1

y=-1/3

y=-1/3

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