(2x)+(10/x)=9

Solution for (2x)+(10/x)=9 equation:

(2x)+(10/x)=9

We move all terms to the left:

(2x)+(10/x)-(9)=0


Domain of the equation: x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

2x+(+10/x)-9=0

We get rid of parentheses

2x+10/x-9=0

We multiply all the terms by the denominator


2x*x-9*x+10=0

We add all the numbers together, and all the variables

-9x+2x*x+10=0

Wy multiply elements

2x^2-9x+10=0

a = 2; b = -9; c = +10;
Δ = b2-4ac
Δ = -92-4·2·10
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-1}{2*2}=\frac{8}{4}
=2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+1}{2*2}=\frac{10}{4}
=2+1/2
$