7(y+1)-2=5(y+1)+2

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Solution for 7(y+1)-2=5(y+1)+2 equation:


Simplifying
7(y + 1) + -2 = 5(y + 1) + 2

Reorder the terms:
7(1 + y) + -2 = 5(y + 1) + 2
(1 * 7 + y * 7) + -2 = 5(y + 1) + 2
(7 + 7y) + -2 = 5(y + 1) + 2

Reorder the terms:
7 + -2 + 7y = 5(y + 1) + 2

Combine like terms: 7 + -2 = 5
5 + 7y = 5(y + 1) + 2

Reorder the terms:
5 + 7y = 5(1 + y) + 2
5 + 7y = (1 * 5 + y * 5) + 2
5 + 7y = (5 + 5y) + 2

Reorder the terms:
5 + 7y = 5 + 2 + 5y

Combine like terms: 5 + 2 = 7
5 + 7y = 7 + 5y

Solving
5 + 7y = 7 + 5y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-5y' to each side of the equation.
5 + 7y + -5y = 7 + 5y + -5y

Combine like terms: 7y + -5y = 2y
5 + 2y = 7 + 5y + -5y

Combine like terms: 5y + -5y = 0
5 + 2y = 7 + 0
5 + 2y = 7

Add '-5' to each side of the equation.
5 + -5 + 2y = 7 + -5

Combine like terms: 5 + -5 = 0
0 + 2y = 7 + -5
2y = 7 + -5

Combine like terms: 7 + -5 = 2
2y = 2

Divide each side by '2'.
y = 1

Simplifying
y = 1

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