(x-1)(3x+5)-(2x-2)=0

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Solution for (x-1)(3x+5)-(2x-2)=0 equation:


Simplifying
(x + -1)(3x + 5) + -1(2x + -2) = 0

Reorder the terms:
(-1 + x)(3x + 5) + -1(2x + -2) = 0

Reorder the terms:
(-1 + x)(5 + 3x) + -1(2x + -2) = 0

Multiply (-1 + x) * (5 + 3x)
(-1(5 + 3x) + x(5 + 3x)) + -1(2x + -2) = 0
((5 * -1 + 3x * -1) + x(5 + 3x)) + -1(2x + -2) = 0
((-5 + -3x) + x(5 + 3x)) + -1(2x + -2) = 0
(-5 + -3x + (5 * x + 3x * x)) + -1(2x + -2) = 0
(-5 + -3x + (5x + 3x2)) + -1(2x + -2) = 0

Combine like terms: -3x + 5x = 2x
(-5 + 2x + 3x2) + -1(2x + -2) = 0

Reorder the terms:
-5 + 2x + 3x2 + -1(-2 + 2x) = 0
-5 + 2x + 3x2 + (-2 * -1 + 2x * -1) = 0
-5 + 2x + 3x2 + (2 + -2x) = 0

Reorder the terms:
-5 + 2 + 2x + -2x + 3x2 = 0

Combine like terms: -5 + 2 = -3
-3 + 2x + -2x + 3x2 = 0

Combine like terms: 2x + -2x = 0
-3 + 0 + 3x2 = 0
-3 + 3x2 = 0

Solving
-3 + 3x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '3' to each side of the equation.
-3 + 3 + 3x2 = 0 + 3

Combine like terms: -3 + 3 = 0
0 + 3x2 = 0 + 3
3x2 = 0 + 3

Combine like terms: 0 + 3 = 3
3x2 = 3

Divide each side by '3'.
x2 = 1

Simplifying
x2 = 1

Take the square root of each side:
x = {-1, 1}

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