7(x-7)+41=7x-8

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Solution for 7(x-7)+41=7x-8 equation: 



7(x-7)+41=7x-8

We move all terms to the left:

7(x-7)+41-(7x-8)=0

We multiply parentheses

7x-(7x-8)-49+41=0

We get rid of parentheses

7x-7x+8-49+41=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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