45=6(3+2b)-(2b-7)

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Solution for 45=6(3+2b)-(2b-7) equation: 



45=6(3+2b)-(2b-7)

We move all terms to the left:

45-(6(3+2b)-(2b-7))=0

We add all the numbers together, and all the variables

-(6(2b+3)-(2b-7))+45=0



We calculate terms in parentheses: -(6(2b+3)-(2b-7)), so:

6(2b+3)-(2b-7)

We multiply parentheses

12b-(2b-7)+18

We get rid of parentheses

12b-2b+7+18

We add all the numbers together, and all the variables

10b+25

Back to the equation:

-(10b+25)



We get rid of parentheses

-10b-25+45=0

We add all the numbers together, and all the variables

-10b+20=0

We move all terms containing b to the left, all other terms to the right

-10b=-20

b=-20/-10

b=+2

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