7(x-5)=(x+2)

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Solution for 7(x-5)=(x+2) equation: 



7(x-5)=(x+2)

We move all terms to the left:

7(x-5)-((x+2))=0

We multiply parentheses

7x-((x+2))-35=0



We calculate terms in parentheses: -((x+2)), so:

(x+2)

We get rid of parentheses

x+2

Back to the equation:

-(x+2)



We get rid of parentheses

7x-x-2-35=0

We add all the numbers together, and all the variables

6x-37=0

We move all terms containing x to the left, all other terms to the right

6x=37

x=37/6

x=6+1/6

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