-5(2+4x)=-4x(6x+4)+2

Solution for -5(2+4x)=-4x(6x+4)+2 equation:

-5(2+4x)=-4x(6x+4)+2

We move all terms to the left:

-5(2+4x)-(-4x(6x+4)+2)=0

We add all the numbers together, and all the variables

-5(4x+2)-(-4x(6x+4)+2)=0

We multiply parentheses

-20x-(-4x(6x+4)+2)-10=0


We calculate terms in parentheses: -(-4x(6x+4)+2), so:

-4x(6x+4)+2

We multiply parentheses

-24x^2-16x+2

Back to the equation:

-(-24x^2-16x+2)


We get rid of parentheses

24x^2+16x-20x-2-10=0

We add all the numbers together, and all the variables

24x^2-4x-12=0

a = 24; b = -4; c = -12;
Δ = b2-4ac
Δ = -42-4·24·(-12)
Δ = 1168
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1168}=\sqrt{16*73}=\sqrt{16}*\sqrt{73}=4\sqrt{73}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-4\sqrt{73}}{2*24}=\frac{4-4\sqrt{73}}{48}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+4\sqrt{73}}{2*24}=\frac{4+4\sqrt{73}}{48}
$