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7(x-5)-6=3(4x+1)+2=
We move all terms to the left:
7(x-5)-6-(3(4x+1)+2)=0
We multiply parentheses
7x-(3(4x+1)+2)-35-6=0
We calculate terms in parentheses: -(3(4x+1)+2), so:We add all the numbers together, and all the variables
3(4x+1)+2
We multiply parentheses
12x+3+2
We add all the numbers together, and all the variables
12x+5
Back to the equation:
-(12x+5)
7x-(12x+5)-41=0
We get rid of parentheses
7x-12x-5-41=0
We add all the numbers together, and all the variables
-5x-46=0
We move all terms containing x to the left, all other terms to the right
-5x=46
x=46/-5
x=-9+1/5
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