(7y-8)=(2y-1)

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Solution for (7y-8)=(2y-1) equation: 



(7y-8)=(2y-1)

We move all terms to the left:

(7y-8)-((2y-1))=0

We get rid of parentheses

7y-((2y-1))-8=0



We calculate terms in parentheses: -((2y-1)), so:

(2y-1)

We get rid of parentheses

2y-1

Back to the equation:

-(2y-1)



We get rid of parentheses

7y-2y+1-8=0

We add all the numbers together, and all the variables

5y-7=0

We move all terms containing y to the left, all other terms to the right

5y=7

y=7/5

y=1+2/5

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