7(x-4)-3(x+2)=4(x-2)

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Solution for 7(x-4)-3(x+2)=4(x-2) equation: 



7(x-4)-3(x+2)=4(x-2)

We move all terms to the left:

7(x-4)-3(x+2)-(4(x-2))=0

We multiply parentheses

7x-3x-(4(x-2))-28-6=0



We calculate terms in parentheses: -(4(x-2)), so:

4(x-2)

We multiply parentheses

4x-8

Back to the equation:

-(4x-8)



We add all the numbers together, and all the variables

4x-(4x-8)-34=0

We get rid of parentheses

4x-4x+8-34=0

We add all the numbers together, and all the variables

-26!=0

There is no solution for this equation

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