2+2/5(k+4)=4

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Solution for 2+2/5(k+4)=4 equation: 



2+2/5(k+4)=4

We move all terms to the left:

2+2/5(k+4)-(4)=0



Domain of the equation: 5(k+4)!=0

k∈R



We add all the numbers together, and all the variables

2/5(k+4)-2=0

We multiply all the terms by the denominator


-2*5(k+4)+2=0

Wy multiply elements

-10k(k+2=0

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