7(x-4)+3x=12

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Solution for 7(x-4)+3x=12 equation: 



7(x-4)+3x=12

We move all terms to the left:

7(x-4)+3x-(12)=0

We add all the numbers together, and all the variables

3x+7(x-4)-12=0

We multiply parentheses

3x+7x-28-12=0

We add all the numbers together, and all the variables

10x-40=0

We move all terms containing x to the left, all other terms to the right

10x=40

x=40/10

x=4

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