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3(2x-1)=5x(7x-1)-2
We move all terms to the left:
3(2x-1)-(5x(7x-1)-2)=0
We multiply parentheses
6x-(5x(7x-1)-2)-3=0
We calculate terms in parentheses: -(5x(7x-1)-2), so:We get rid of parentheses
5x(7x-1)-2
We multiply parentheses
35x^2-5x-2
Back to the equation:
-(35x^2-5x-2)
-35x^2+6x+5x+2-3=0
We add all the numbers together, and all the variables
-35x^2+11x-1=0
a = -35; b = 11; c = -1;
Δ = b2-4ac
Δ = 112-4·(-35)·(-1)
Δ = -19
Delta is less than zero, so there is no solution for the equation
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