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4(x-3)=2(3x-5)
We move all terms to the left:
4(x-3)-(2(3x-5))=0
We multiply parentheses
4x-(2(3x-5))-12=0
We calculate terms in parentheses: -(2(3x-5)), so:We get rid of parentheses
2(3x-5)
We multiply parentheses
6x-10
Back to the equation:
-(6x-10)
4x-6x+10-12=0
We add all the numbers together, and all the variables
-2x-2=0
We move all terms containing x to the left, all other terms to the right
-2x=2
x=2/-2
x=-1
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