7(x-3)=3(4-2x)=-8

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Solution for 7(x-3)=3(4-2x)=-8 equation: 



7(x-3)=3(4-2x)=-8

We move all terms to the left:

7(x-3)-(3(4-2x))=0

We add all the numbers together, and all the variables

7(x-3)-(3(-2x+4))=0

We multiply parentheses

7x-(3(-2x+4))-21=0



We calculate terms in parentheses: -(3(-2x+4)), so:

3(-2x+4)

We multiply parentheses

-6x+12

Back to the equation:

-(-6x+12)



We get rid of parentheses

7x+6x-12-21=0

We add all the numbers together, and all the variables

13x-33=0

We move all terms containing x to the left, all other terms to the right

13x=33

x=33/13

x=2+7/13

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