7(4y+2)=36

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Solution for 7(4y+2)=36 equation: 



7(4y+2)=36

We move all terms to the left:

7(4y+2)-(36)=0

We multiply parentheses

28y+14-36=0

We add all the numbers together, and all the variables

28y-22=0

We move all terms containing y to the left, all other terms to the right

28y=22

y=22/28

y=11/14

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