7(x-3)+20=8-3(5-2x)

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Solution for 7(x-3)+20=8-3(5-2x) equation: 



7(x-3)+20=8-3(5-2x)

We move all terms to the left:

7(x-3)+20-(8-3(5-2x))=0

We add all the numbers together, and all the variables

7(x-3)-(8-3(-2x+5))+20=0

We multiply parentheses

7x-(8-3(-2x+5))-21+20=0



We calculate terms in parentheses: -(8-3(-2x+5)), so:

8-3(-2x+5)

determiningTheFunctionDomain
-3(-2x+5)+8

We multiply parentheses

6x-15+8

We add all the numbers together, and all the variables

6x-7

Back to the equation:

-(6x-7)



We add all the numbers together, and all the variables

7x-(6x-7)-1=0

We get rid of parentheses

7x-6x+7-1=0

We add all the numbers together, and all the variables

x+6=0

We move all terms containing x to the left, all other terms to the right

x=-6

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