7(x-2)=4(x+1)+x

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Solution for 7(x-2)=4(x+1)+x equation: 



7(x-2)=4(x+1)+x

We move all terms to the left:

7(x-2)-(4(x+1)+x)=0

We multiply parentheses

7x-(4(x+1)+x)-14=0



We calculate terms in parentheses: -(4(x+1)+x), so:

4(x+1)+x

We add all the numbers together, and all the variables

x+4(x+1)

We multiply parentheses

x+4x+4

We add all the numbers together, and all the variables

5x+4

Back to the equation:

-(5x+4)



We get rid of parentheses

7x-5x-4-14=0

We add all the numbers together, and all the variables

2x-18=0

We move all terms containing x to the left, all other terms to the right

2x=18

x=18/2

x=9

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