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5x^2+70x+225=0
a = 5; b = 70; c = +225;
Δ = b2-4ac
Δ = 702-4·5·225
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{400}=20$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(70)-20}{2*5}=\frac{-90}{10} =-9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(70)+20}{2*5}=\frac{-50}{10} =-5 $
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