7(x-2)=3(x+12)-2

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Solution for 7(x-2)=3(x+12)-2 equation: 



7(x-2)=3(x+12)-2

We move all terms to the left:

7(x-2)-(3(x+12)-2)=0

We multiply parentheses

7x-(3(x+12)-2)-14=0



We calculate terms in parentheses: -(3(x+12)-2), so:

3(x+12)-2

We multiply parentheses

3x+36-2

We add all the numbers together, and all the variables

3x+34

Back to the equation:

-(3x+34)



We get rid of parentheses

7x-3x-34-14=0

We add all the numbers together, and all the variables

4x-48=0

We move all terms containing x to the left, all other terms to the right

4x=48

x=48/4

x=12

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