7(x-2)-3=2(5+4x)

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Solution for 7(x-2)-3=2(5+4x) equation: 



7(x-2)-3=2(5+4x)

We move all terms to the left:

7(x-2)-3-(2(5+4x))=0

We add all the numbers together, and all the variables

7(x-2)-(2(4x+5))-3=0

We multiply parentheses

7x-(2(4x+5))-14-3=0



We calculate terms in parentheses: -(2(4x+5)), so:

2(4x+5)

We multiply parentheses

8x+10

Back to the equation:

-(8x+10)



We add all the numbers together, and all the variables

7x-(8x+10)-17=0

We get rid of parentheses

7x-8x-10-17=0

We add all the numbers together, and all the variables

-1x-27=0

We move all terms containing x to the left, all other terms to the right

-x=27

x=27/-1

x=-27

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