7(x+5)-4=5x-2(x+3)

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Solution for 7(x+5)-4=5x-2(x+3) equation: 



7(x+5)-4=5x-2(x+3)

We move all terms to the left:

7(x+5)-4-(5x-2(x+3))=0

We multiply parentheses

7x-(5x-2(x+3))+35-4=0



We calculate terms in parentheses: -(5x-2(x+3)), so:

5x-2(x+3)

We multiply parentheses

5x-2x-6

We add all the numbers together, and all the variables

3x-6

Back to the equation:

-(3x-6)



We add all the numbers together, and all the variables

7x-(3x-6)+31=0

We get rid of parentheses

7x-3x+6+31=0

We add all the numbers together, and all the variables

4x+37=0

We move all terms containing x to the left, all other terms to the right

4x=-37

x=-37/4

x=-9+1/4

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