1/2(11x-3)=8x+6

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Solution for 1/2(11x-3)=8x+6 equation: 



1/2(11x-3)=8x+6

We move all terms to the left:

1/2(11x-3)-(8x+6)=0



Domain of the equation: 2(11x-3)!=0

x∈R



We get rid of parentheses

1/2(11x-3)-8x-6=0

We multiply all the terms by the denominator


-8x*2(11x-3)-6*2(11x-3)+1=0

Wy multiply elements

-16x^2(1-12x(1+1=0

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