3(s-1)+2(2s+4)=-3(s-5)

Solution for 3(s-1)+2(2s+4)=-3(s-5) equation:

3(s-1)+2(2s+4)=-3(s-5)

We move all terms to the left:

3(s-1)+2(2s+4)-(-3(s-5))=0

We multiply parentheses

3s+4s-(-3(s-5))-3+8=0


We calculate terms in parentheses: -(-3(s-5)), so:

-3(s-5)

We multiply parentheses

-3s+15

Back to the equation:

-(-3s+15)


We add all the numbers together, and all the variables

7s-(-3s+15)+5=0

We get rid of parentheses

7s+3s-15+5=0

We add all the numbers together, and all the variables

10s-10=0

We move all terms containing s to the left, all other terms to the right

10s=10

s=10/10

s=1