7(x+5)+1=4(x+2)

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Solution for 7(x+5)+1=4(x+2) equation: 



7(x+5)+1=4(x+2)

We move all terms to the left:

7(x+5)+1-(4(x+2))=0

We multiply parentheses

7x-(4(x+2))+35+1=0



We calculate terms in parentheses: -(4(x+2)), so:

4(x+2)

We multiply parentheses

4x+8

Back to the equation:

-(4x+8)



We add all the numbers together, and all the variables

7x-(4x+8)+36=0

We get rid of parentheses

7x-4x-8+36=0

We add all the numbers together, and all the variables

3x+28=0

We move all terms containing x to the left, all other terms to the right

3x=-28

x=-28/3

x=-9+1/3

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