7(x+4)=5(2x-3)+11

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Solution for 7(x+4)=5(2x-3)+11 equation: 



7(x+4)=5(2x-3)+11

We move all terms to the left:

7(x+4)-(5(2x-3)+11)=0

We multiply parentheses

7x-(5(2x-3)+11)+28=0



We calculate terms in parentheses: -(5(2x-3)+11), so:

5(2x-3)+11

We multiply parentheses

10x-15+11

We add all the numbers together, and all the variables

10x-4

Back to the equation:

-(10x-4)



We get rid of parentheses

7x-10x+4+28=0

We add all the numbers together, and all the variables

-3x+32=0

We move all terms containing x to the left, all other terms to the right

-3x=-32

x=-32/-3

x=10+2/3

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