10.x2=6x=5=0

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Solution for 10.x2=6x=5=0 equation:



10.x^2=6x=5=0
We move all terms to the left:
10.x^2-(6x)=0
a = 10.; b = -6; c = 0;
Δ = b2-4ac
Δ = -62-4·10.·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-6}{2*10.}=\frac{0}{20} =0 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+6}{2*10.}=\frac{12}{20} =3/5 $

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