7(x+3)=2-4(x-1)

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Solution for 7(x+3)=2-4(x-1) equation: 



7(x+3)=2-4(x-1)

We move all terms to the left:

7(x+3)-(2-4(x-1))=0

We multiply parentheses

7x-(2-4(x-1))+21=0



We calculate terms in parentheses: -(2-4(x-1)), so:

2-4(x-1)

determiningTheFunctionDomain
-4(x-1)+2

We multiply parentheses

-4x+4+2

We add all the numbers together, and all the variables

-4x+6

Back to the equation:

-(-4x+6)



We get rid of parentheses

7x+4x-6+21=0

We add all the numbers together, and all the variables

11x+15=0

We move all terms containing x to the left, all other terms to the right

11x=-15

x=-15/11

x=-1+4/11

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