7(x+3)=2(x+28)

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Solution for 7(x+3)=2(x+28) equation:


Simplifying
7(x + 3) = 2(x + 28)

Reorder the terms:
7(3 + x) = 2(x + 28)
(3 * 7 + x * 7) = 2(x + 28)
(21 + 7x) = 2(x + 28)

Reorder the terms:
21 + 7x = 2(28 + x)
21 + 7x = (28 * 2 + x * 2)
21 + 7x = (56 + 2x)

Solving
21 + 7x = 56 + 2x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-2x' to each side of the equation.
21 + 7x + -2x = 56 + 2x + -2x

Combine like terms: 7x + -2x = 5x
21 + 5x = 56 + 2x + -2x

Combine like terms: 2x + -2x = 0
21 + 5x = 56 + 0
21 + 5x = 56

Add '-21' to each side of the equation.
21 + -21 + 5x = 56 + -21

Combine like terms: 21 + -21 = 0
0 + 5x = 56 + -21
5x = 56 + -21

Combine like terms: 56 + -21 = 35
5x = 35

Divide each side by '5'.
x = 7

Simplifying
x = 7

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