1/3(10y-2)+1/12(8y+13)

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Solution for 1/3(10y-2)+1/12(8y+13) equation: 


y in (-oo:+oo)

(1/3)*(10*y-2)+(1/12)*(8*y+13) = 0

1/3*(10*y-2)+1/12*(8*y+13) = 0

1/3*(10*y-2)+1/12*(8*y+13) = 0

4*y+5/12 = 0

4*y+5/12 = 0

4*y+5/12 = 0 // - 5/12

4*y = -5/12 // : 4

y = -5/12/4

y = -5/48

y = -5/48

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