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7(x+3)-6=2x+5(2+x)
We move all terms to the left:
7(x+3)-6-(2x+5(2+x))=0
We add all the numbers together, and all the variables
7(x+3)-(2x+5(x+2))-6=0
We multiply parentheses
7x-(2x+5(x+2))+21-6=0
We calculate terms in parentheses: -(2x+5(x+2)), so:We add all the numbers together, and all the variables
2x+5(x+2)
We multiply parentheses
2x+5x+10
We add all the numbers together, and all the variables
7x+10
Back to the equation:
-(7x+10)
7x-(7x+10)+15=0
We get rid of parentheses
7x-7x-10+15=0
We add all the numbers together, and all the variables
5!=0
There is no solution for this equation
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