7(x+2)=3(4x-2)

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Solution for 7(x+2)=3(4x-2) equation: 



7(x+2)=3(4x-2)

We move all terms to the left:

7(x+2)-(3(4x-2))=0

We multiply parentheses

7x-(3(4x-2))+14=0



We calculate terms in parentheses: -(3(4x-2)), so:

3(4x-2)

We multiply parentheses

12x-6

Back to the equation:

-(12x-6)



We get rid of parentheses

7x-12x+6+14=0

We add all the numbers together, and all the variables

-5x+20=0

We move all terms containing x to the left, all other terms to the right

-5x=-20

x=-20/-5

x=+4

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