7(x+2)+4x=2(x-2)

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Solution for 7(x+2)+4x=2(x-2) equation: 



7(x+2)+4x=2(x-2)

We move all terms to the left:

7(x+2)+4x-(2(x-2))=0

We add all the numbers together, and all the variables

4x+7(x+2)-(2(x-2))=0

We multiply parentheses

4x+7x-(2(x-2))+14=0



We calculate terms in parentheses: -(2(x-2)), so:

2(x-2)

We multiply parentheses

2x-4

Back to the equation:

-(2x-4)



We add all the numbers together, and all the variables

11x-(2x-4)+14=0

We get rid of parentheses

11x-2x+4+14=0

We add all the numbers together, and all the variables

9x+18=0

We move all terms containing x to the left, all other terms to the right

9x=-18

x=-18/9

x=-2

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