5(x-3)+6(x-12)+2(x+2)=6.4

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Solution for 5(x-3)+6(x-12)+2(x+2)=6.4 equation: 



5(x-3)+6(x-12)+2(x+2)=6.4

We move all terms to the left:

5(x-3)+6(x-12)+2(x+2)-(6.4)=0

We add all the numbers together, and all the variables

5(x-3)+6(x-12)+2(x+2)-6.4=0

We multiply parentheses

5x+6x+2x-15-72+4-6.4=0

We add all the numbers together, and all the variables

13x-89.4=0

We move all terms containing x to the left, all other terms to the right

13x=89.4

x=89.4/13

x=6+8.1428571428571/9.2857142857142

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