7(x+1)=36(2x-1)

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Solution for 7(x+1)=36(2x-1) equation: 



7(x+1)=36(2x-1)

We move all terms to the left:

7(x+1)-(36(2x-1))=0

We multiply parentheses

7x-(36(2x-1))+7=0



We calculate terms in parentheses: -(36(2x-1)), so:

36(2x-1)

We multiply parentheses

72x-36

Back to the equation:

-(72x-36)



We get rid of parentheses

7x-72x+36+7=0

We add all the numbers together, and all the variables

-65x+43=0

We move all terms containing x to the left, all other terms to the right

-65x=-43

x=-43/-65

x=43/65

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