1/2x,-7=1/3(x-12)

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Solution for 1/2x,-7=1/3(x-12) equation: 



1/2x.-7=1/3(x-12)

We move all terms to the left:

1/2x.-7-(1/3(x-12))=0



Domain of the equation: 2x.!=0

x!=0/1

x!=0

x∈R





Domain of the equation: 3(x-12))!=0

x∈R



We calculate fractions


(3xx/(2x.*3(x-12)))+(-(1*2x.)/(2x.*3(x-12)))-7=0



We calculate terms in parentheses: +(3xx/(2x.*3(x-12))), so:

3xx/(2x.*3(x-12))

We multiply all the terms by the denominator


3xx

Back to the equation:

+(3xx)





We calculate terms in parentheses: +(-(1*2x.)/(2x.*3(x-12))), so:

-(1*2x.)/(2x.*3(x-12))

We add all the numbers together, and all the variables

-(+1*2x.)/(2x.*3(x-12))

We multiply all the terms by the denominator


-(+1*2x.)

We get rid of parentheses

-1*2x.

Wy multiply elements

-2x

Back to the equation:

+(-2x)



We get rid of parentheses

3xx-2x-7=0

We add all the numbers together, and all the variables

-2x+3xx-7=0

We move all terms containing x to the left, all other terms to the right

-2x+3xx=7

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