15(2x-19)=10(x-9)

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Solution for 15(2x-19)=10(x-9) equation: 



15(2x-19)=10(x-9)

We move all terms to the left:

15(2x-19)-(10(x-9))=0

We multiply parentheses

30x-(10(x-9))-285=0



We calculate terms in parentheses: -(10(x-9)), so:

10(x-9)

We multiply parentheses

10x-90

Back to the equation:

-(10x-90)



We get rid of parentheses

30x-10x+90-285=0

We add all the numbers together, and all the variables

20x-195=0

We move all terms containing x to the left, all other terms to the right

20x=195

x=195/20

x=9+3/4

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