7(x+1)=13+4(3x-2)=

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Solution for 7(x+1)=13+4(3x-2)= equation: 



7(x+1)=13+4(3x-2)=

We move all terms to the left:

7(x+1)-(13+4(3x-2))=0

We multiply parentheses

7x-(13+4(3x-2))+7=0



We calculate terms in parentheses: -(13+4(3x-2)), so:

13+4(3x-2)

determiningTheFunctionDomain
4(3x-2)+13

We multiply parentheses

12x-8+13

We add all the numbers together, and all the variables

12x+5

Back to the equation:

-(12x+5)



We get rid of parentheses

7x-12x-5+7=0

We add all the numbers together, and all the variables

-5x+2=0

We move all terms containing x to the left, all other terms to the right

-5x=-2

x=-2/-5

x=2/5

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