7(w+3)=-6(2w-4)+7w

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Solution for 7(w+3)=-6(2w-4)+7w equation: 



7(w+3)=-6(2w-4)+7w

We move all terms to the left:

7(w+3)-(-6(2w-4)+7w)=0

We multiply parentheses

7w-(-6(2w-4)+7w)+21=0



We calculate terms in parentheses: -(-6(2w-4)+7w), so:

-6(2w-4)+7w

We add all the numbers together, and all the variables

7w-6(2w-4)

We multiply parentheses

7w-12w+24

We add all the numbers together, and all the variables

-5w+24

Back to the equation:

-(-5w+24)



We get rid of parentheses

7w+5w-24+21=0

We add all the numbers together, and all the variables

12w-3=0

We move all terms containing w to the left, all other terms to the right

12w=3

w=3/12

w=1/4

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