-3(v+3)=-3(2v-2)+9v

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Solution for -3(v+3)=-3(2v-2)+9v equation: 



-3(v+3)=-3(2v-2)+9v

We move all terms to the left:

-3(v+3)-(-3(2v-2)+9v)=0

We multiply parentheses

-3v-(-3(2v-2)+9v)-9=0



We calculate terms in parentheses: -(-3(2v-2)+9v), so:

-3(2v-2)+9v

We add all the numbers together, and all the variables

9v-3(2v-2)

We multiply parentheses

9v-6v+6

We add all the numbers together, and all the variables

3v+6

Back to the equation:

-(3v+6)



We get rid of parentheses

-3v-3v-6-9=0

We add all the numbers together, and all the variables

-6v-15=0

We move all terms containing v to the left, all other terms to the right

-6v=15

v=15/-6

v=-2+1/2

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